buf.writeBigUInt64LE(value[, offset])

• value <bigint> 要写入 buf 的数字。
• offset <integer> 开始写入之前要跳过的字节数。 必须满足：0 <= offset <= buf.length - 8。 默认值: 0。
• 返回: <integer> offset 加上写入的字节数。

将 value 作为小端序写入 buf 中指定的 offset

const buf = Buffer.allocUnsafe(8);

buf.writeBigUInt64LE(0xdecafafecacefaden, 0);

console.log(buf);
// 打印: <Buffer de fa ce ca fe fa ca de>

此函数也可在 writeBigUint64LE 别名下使用。

• value <bigint> Number to be written to buf.
• offset <integer> Number of bytes to skip before starting to write. Must satisfy: 0 <= offset <= buf.length - 8. Default: 0.
• Returns: <integer> offset plus the number of bytes written.

Writes value to buf at the specified offset as little-endian

const buf = Buffer.allocUnsafe(8);

buf.writeBigUInt64LE(0xdecafafecacefaden, 0);

console.log(buf);
// Prints: <Buffer de fa ce ca fe fa ca de>

This function is also available under the writeBigUint64LE alias.